Source code for rule_engine.parser.utilities

#!/usr/bin/env python3
# -*- coding: utf-8 -*-
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#  rule_engine/parser/utilities.py
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import binascii
import datetime
import decimal
import re

from . import errors
from ..types.coercion import _to_decimal

import dateutil.parser

_sub_regex = r'[0-9]+([,.][0-9]+)?'
timedelta_regex = (
        r'P(?!\b)'
        r'(?P<weeks>' + _sub_regex + r'W)?'
        r'(?P<days>' + _sub_regex + r'D)?'
        r'(T'
        r'(?P<hours>' + _sub_regex + r'H)?'
        r'(?P<minutes>' + _sub_regex + r'M)?'
        r'(?P<seconds>' + _sub_regex + r'S)?'
        r')?'
)

[docs] def parse_datetime(string: str, default_timezone: datetime.tzinfo) -> datetime.datetime: """ Parse a timestamp string. If the timestamp does not specify a timezone, *default_timezone* is used. :param str string: The string to parse. :param datetime.tzinfo default_timezone: The default timezone to set. :rtype: datetime.datetime """ try: dt = dateutil.parser.isoparse(string) except ValueError: raise errors.DatetimeSyntaxError('invalid datetime literal', string) from None if dt.tzinfo is None: dt = dt.replace(tzinfo=default_timezone) return dt
# a binary, octal or hexadecimal literal with the same digits and underscores that Python allows, followed by the # trailing whitespace that was accepted when these values were parsed with ast.literal_eval: any spaces, tabs, form feeds # and line breaks, except that Python rejected a last line, after a line break, that ends with a space or tab. The # character classes are ASCII only, so int() never sees the other digits and whitespace that it accepts. _prefixed_int_regex = re.compile( r'(0(?:b(?:_?[01])+|o(?:_?[0-7])+|x(?:_?[0-9a-fA-F])+))' r'[ \t\f]*(?:[\r\n](?:[ \t\f]*[\r\n])*(?:[ \t\f]*\f)?)?' ) def _parse_float(string: str) -> decimal.Decimal | int: # binary, octal and hexadecimal values are returned as an int so the caller can convert it using the correct limit if re.match('^0[0-9]', string): raise errors.FloatSyntaxError('invalid floating point literal (leading zeros in decimal literals are not permitted)', string) if re.match('^0[box]', string): match = _prefixed_int_regex.fullmatch(string) if match is None: raise errors.FloatSyntaxError('invalid floating point literal', string) return int(match.group(1), 0) try: return decimal.Decimal(string) except Exception: raise errors.FloatSyntaxError('invalid floating point literal', string) from None
[docs] def parse_float(string: str, *, int_max_digits: int | None = None) -> decimal.Decimal: """ Parse a literal string representing a floating point value. .. versionchanged:: 5.2.0 Added the *int_max_digits* parameter. :param str string: The string to parse. :param int int_max_digits: The maximum number of digits that a binary, octal or hexadecimal literal can have once converted to a decimal value. See :py:func:`~rule_engine.types.coerce_value` for details. :rtype: decimal.Decimal :raises ~rule_engine.errors.ArithmeticError: *string* is a binary, octal or hexadecimal literal with more digits than allowed by *int_max_digits*. """ return _to_decimal(_parse_float(string), int_max_digits)
[docs] def parse_timedelta(string: str) -> datetime.timedelta: """ Parse a literal string representing a time period in the ISO-8601 duration format. :param str string: The string to parse. :rtype: datetime.timedelta """ if string == "P": raise errors.TimedeltaSyntaxError('empty timedelta string', string) match = re.match("^" + timedelta_regex + "$", string) if not match: raise errors.TimedeltaSyntaxError('invalid timedelta string', string) groups: dict[str, float] = { key: float((val if val is not None else "0n")[:-1].replace(',', '.')) for key, val in match.groupdict().items() } return datetime.timedelta( weeks=groups['weeks'], days=groups['days'], hours=groups['hours'], minutes=groups['minutes'], seconds=groups['seconds'], )